Answer:
Explanation:
Given that:
The Half-life of = is less than that of
Although we are not given any value about the present weight of .
So, consider the present weight in the percentage of to be y%
Then, the time elapsed to get the present weight of =
Therefore;
here;
= Number of radioactive atoms relating to the weight of y of
Thus:
--- (1)
However, Suppose the time elapsed from the initial stage to arrive at the weight of the percentage of to be =
Then:
---- (2)
here;
= Number of radioactive atoms of relating to 3.0 a/o weight
Now, equating equation (1) and (2) together, we have:
replacing the half-life of =
( since )
∴
The time elapsed signifies how long the isotopic abundance of 235U equal to 3.0 a/o
Thus, The time elapsed is
Answer : The volume of gas occupy at is, 1.25 L
Explanation :
Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Therefore, the volume of gas occupy at is, 1.25 L
Explanation:
(a) The given data is as follows.
Pressure on top () = 140 bar = (as 1 bar = )
Temperature = = (15 + 273) K = 288 K
Density of gas =
= 0.4548
=
=
Hence, pressure at the natural gas-oil interface is .
(b) At the bottom of the tank,
= 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]
=
= 309.8 bar
Hence, at the bottom of the well at pressure is 309.8 bar.
The answer would be D. because when an acid and base mix the start to cancel each other out causing it to neutralize
Maybe molecules one electron