Answer:
Chief Hopper
Explanation:
Mike travels at a constant speed of 3.1 m/s. To find how long it takes him to reach the school, we need to find the distance he travels. We can do this using Pythagorean theorem.
a² + b² = c²
(1000 m)² + (900 m)² = c²
c ≈ 1345 m
So the time is:
v = d / t
3.1 m/s = 1345 m / t
t ≈ 434 s
Next, Chief Hopper travels a total distance of 1900 m, starting at rest and accelerating at 0.028 m/s². So we can use constant acceleration equation to find the time.
d = v₀ t + ½ at²
1900 m = (0 m/s) t + ½ (0.028 m/s²) t²
t ≈ 368 s
So Chief Hopper reaches the school first, approximately 66 seconds before Mike does.
Answer: They will have equal final angular velocity.
Explanation:
Since the discs starts from rest and rotates about a fixed axis, they are subject to a constant net torque. The work done by the torque during the second revolution is as the work done during the first revolution.
The four disc will turn through equal angles in equal times.
Answer:
ne diyorsun anlamadım cevap anhtarımı
To find out the weight of the object, you'll need to slide the weight poises until the pointer is at zero again. Start with the two heavier weight poises and then use the lightest one to do the fine tuning. Our triple beam balance and the Ohaus triple beam balance are accurate to 0.1 grams.
Correct question:
A child bounces a 57 g superball on the sidewalk. The velocity change of the superball is from 24 m/s downward to 11 m/s upward. If the contact time with the sidewalk is 1/800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? Answer in units of N.
Answer:
The magnitude of the average force exerted on the superball by the sidewalk is 592.8 N
Explanation:
Given;
mass of the superball, m = 57 g = 0.057 kg
initial velocity of the superball, u = 24 m/s
final velocity of the superball, v = 11 m/s
contact time with the sidewalk, t = 1 / 800 s
To determine the magnitude of the average force exerted on the superball by the sidewalk, we apply Newton's second law of motion;
F = ma
Therefore, the magnitude of the average force exerted on the superball by the sidewalk is 592.8 N