Let l and l-6 be the length and width, respectively, of the rectangle. Then:
l(l-6)=40
l²-6l-40=0
(l-10)(l+4)=0
l=10,-4
The rectangle is 10" by 4". ☺☺☺☺
Fidn volume
V=hpir^2
d/2=r
1.4/2=0.7=r
height=3.5
V=3.5*3.14*0.7^2
V=5.3851
1.5 times t=5.3851
divide both sides by 1.5
t=3.59
round
t=4
4 minutes
(2p + 7)(3p-9)
2p x 3p= 6p^2
2p x -9= -18p
7 x 3p=21p
7 x -9=-63
6p^2 - 18p + 21p - 63
6p^2 + 3p -63 is the answer.
Answer:
2
----------
5w^11
Step-by-step explanation:
8/20 reduces to 2/5, and (w^(-2)) / w^9 becomes 1 / w^11.
Overall, #20 reduces to:
2
----------
5w^11
Recall the rule of exponents:
w^a
----------- = w^(a-b)
w^b
and note that
w^(-2)
------------ = w^(-2-9) = w^(-11) (same as above)
w^9
