6x+8y=-32
8y=-32-6x
8y/8 -6x/8
y=-3/4x-4
Let cos x = a, then
2a^2 + a - 1 = 0,
solving the quadratic equation, we have:
a = 0.5 or -1.
i.e. cos x = 0.5 or cos x = -1
for cos x = 0.5,
x = pi/3, 2pi - pi/3 = pi/3, 5pi/3
for cos x = -1,
x = pi
therefore, x = pi, pi/3, 5pi/3
Answer: B
Substitute 3 into the expression for c and -4 for d. So, 2c/d = 2(3)/(-4) = 6/-4 = -3/2. The answer is -3/2.
X =blank degrees is the answer
Two angles are called complementary if their measures add to 90 degrees, and called supplementary if their measures add to 180 degrees.
In radians this are
To find the complement of 3π/4, subtract it by π/2
To find the supplement of 3π/4, subtract it by π.