The Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x 
Kg
<h3>
Relationship between Linear and angular speed</h3>
Linear speed is the product of angular speed and the maximum displacement of the particle. That is,
V = Wr
Where
Given that the earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.
a) To determine the Earth’s average orbital speed, we will make use of the below formula to calculate angular speed
W = 2
/T
W = (2 x 3.143) / (365.26 x 24)
W = 6.283 / 876624
W = 7.2 x 
Rad/hr
The Earth’s average orbital speed V = Wr
V = 7.2 x x 149.6 x 
V = 107225.5 kilometers per hours.
b) Based on the information given in this question, to calculate the approximate mass of the Sun, we will use Kepler's 3rd law
M = (4
) / G
M = (4 x 9.8696 x 3.35 x ) / (6.67 x 
x 7.68 x 
<em>)</em>
<em>M = 1.32 x </em>
/ 51.226
M = 2.58 x Kg
Therefore, the Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x Kg
Learn more about Orbital Speed here: brainly.com/question/22247460
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Answer:
32
Explanation:
the atomic mass is the number of protons and neutrons in the nucleus of an atom
so we will add 16 + 16 = 32
<h3>Answer: </h3>
(a)
<h3>Explanation </h3>
- Newtons First Law can be written as the formula
since acceleration is the changing of velocity as its formula is
Thus, a force must be acting on an accelerating/decelerating object
- It is not mass as the mass does not act on the object but rather the mass is acting on the surface of the ground.
- Changing velocity is already acceleration
- inertia is the term used to describe Newtons first law
Answer:
Explanation:
Radius of circular path of coin R = 12.5 x 10⁻²,
coefficient of static friction μs = .33
In order that the coin rotates in circular path , it requires centripetal force which is provided by friction. As speed of rotation increases , force of friction also increases to provide it required centripetal force. When the speed of rotation becomes too high so that frictional force can not compensate the increase in centripetal force then coin will start slipping or it starts moving with respect to turntable.
b ) At this point of time
centripetal force = limiting force of friction
mω² R = μs mg , m is mass of the coin , ω is angular velocity ,
ω² R = μs g
ω² x 12.5 x 10⁻², = .33 x 9.8
ω² = .33 x 9.8 / 12.5 x 10⁻²,
= 25.87
ω = 5.08 rad / s
2π / T = 5.08
T = 2π / 5.08
= 1.23 s .
