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-Dominant- [34]

3 years ago

11

I am one of the most dynamic processes of Earth. I help recycle Earth's materials. I move Earth's crustal plates, creating many

different geological surface features. I am also the cause of natural disasters, such as earthquakes and volcanoes. What am I?

2 answers:

Sergio039 [100]3 years ago

7 0

I Can only think of tectonic plates or gravity

spayn [35]3 years ago

5 0

Continental Drift.. ✌

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If a charged particle is moving parallel to a magnetic field, it experiences

aleksandr82 [10.1K]

Answer:it experiences no force

Explanation:

a charge moving in a direction parallel to the magnetic field experience no force.since the angle e is 0,force would also be 0

3 0

2 years ago

1. Which of the following is not an acceptable Physical Education activity?

Dmitrij [34]

The answer is A

Explanation:
Vacuuming doesn’t involve a lot of physical movements.

3 0

2 years ago

Read 2 more answers

HELP PLZ ASAP!!!!!

zubka84 [21]

Answer:

C. Oxygen combines with carbon dioxide

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B i o l o g y

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Hope it helps

5 0

2 years ago

A bullet is fired at an angle θ above the horizontal with an initial velocity of 800 m/s from the top of an 80 m high tower. Wha

Irina-Kira [14]

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1 year ago

A long, rigid conductor, lying along the x-axis, carries a current of 7.0 A in the negative direction. A magnetic field B is pre

Alisiya [41]

Answer:

0.546 $\hat k$

Explanation:

From the given information:

The force on a given current-carrying conductor is:

$F = I ( \L \limits ^ {\to } \times B ^{\to})\\ \\ dF = I(dL\limits ^ {\to } \times B ^{\to})$

where the length usually in negative (x) direction can be computed as

$\L ^ {\to } = -x\hat i \\dL\limits ^ {\to }- dx\hat i$

Now, taking the integral of the force between x = 1.0 m and x = 3.0 m to get the value of the force, we have:

$\int dF = \int ^3_1 I ( dL^{\to} \times B ^{\to})$

$F = I \int^3_1 ( -dx \hat i ) \times ( 4.0 \hat i + 9.0 \ x^2 \hat j)$

$F = I \int^3_1 - 9.0x^2 \ dx \hat k$

$F = I (9.0) \bigg [\dfrac{x^3}{3} \bigg ] ^3_1 \hat k$

$F = I (9.0) \bigg [\dfrac{3^3}{3} - \dfrac{1^3}{3} \bigg ] \hat k$

where;

current I = 7.0 A

$F = (7.0 \ A) (9.0) \bigg [\dfrac{27}{3} - \dfrac{1}{3} \bigg ] \hat k$

$F = (7.0 \ A) (9.0) \bigg [\dfrac{26}{3} \bigg ] \hat k$

F = 546 × 10⁻³ T/mT $\hat k$

F = 0.546 $\hat k$

4 0

2 years ago