Explanation:
As per the problem,
When q > 0 then -q is a negative charge . Since, change in potential energy (
) increases.
or, 
> 0
or, 
Therefore, both positive and negative charge will move from 
to 
and as 
so both of them move through a negative potential difference.
Thus, we can conclude that the true statements are as follows.
- The positively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).
- The negatively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).
The heat capacity of the silver spoon at the given temperature difference is 817.65 J.
<h3>
Heat capacity of the silver spoon</h3>
The heat capacity of theb silver spoon is the quantity of heat absorbed by the silver spoon. The heat capacity of the silver spoon at the given temperature difference is calculated as follows;
Q = mcΔθ
where;
- m is mass of the spoon
- c is specific heat capacity of silver = 0.237 J/g⁰C
- Δθ is change in temperature
Q = 50 x 0.237 x (89 - 20)
Q = 817.65 J
Thus, the heat capacity of the silver spoon at the given temperature difference is 817.65 J.
Learn more about heat capacity here: brainly.com/question/16559442
Answer:
The horse is going at 12.72 m/s speed.
Explanation:
The initial speed of the horse (u) = 3 m/s
The acceleration of the horse (a)= 5 m/
The displacement( it is assumed it is moving in a straight line)(s)= 15.3 m
Applying the second equation of motion to find out the time,
Solving this quadratic equation, we get time(t)=1.945 s, the other negative time is neglected.
Now applying first equation of motion, to find out the final velocity,
v=12.72 m/s
The horse travels at a speed of 12.72 m/s after covering the given distance.
Answer:
- The gravity does a work of - 117.6 Joules.
- The tension does not do work as the force is perpendicular to the direction of motion at any point in the trajectory.
Explanation:
The work done by the gravity simply is the difference in gravitational potential energy multiplied by -1:
where m is the mass of the ball, g is the acceleration due to gravity, 
is the final height and 
is the initial height.
So, if the radius is 2.00 m, then the difference of height will be 4 meters:
As the tension is perpendicular to the velocity of the ball, the force is always perpendicular to the direction of motion. So, the differential of work will be:
I think it is either D) or E)
But i am going to go with E)
