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Scorpion4ik [409]

2 years ago

7

I don’t know how to do the first one

2 answers:

Tema [17]2 years ago

4 0

Answer:

10.9 people per square mile

Step-by-step explanation:

If you look at the chart, there are 41.5 people per square mile in Colorado and 52.4 people per square mile in Iowa. To find the answer, simply subtract:

52.4 - 41.5 = 10.9

Hatshy [7]2 years ago

4 0

Answer:

Hello!! The answer for #15 is 10.9 people per square mile.

Step-by-step explanation:

First, set up your equation. Then subtract left-to-right. You'll need to regroup! You can't subtract 5 from 4, so you'll need to take ten from 2. This will make your tenths place .9 and your tens place 0. Then just subtract 4 from 5 to get 1 in your ones place.

Hope this helped!!

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Last year, 350 people come to see a spring concert at REL. The cost per ticket was $5.00. The orchestra committee wants to incre

Anit [1.1K]

Let 0.25x is the price increase. Therefore, the number of attendees will be 350-10x and the revenue R=(350-10x)*(5+0.25x)=1750+37.5x-2.5x^2. This parabola has maximum at x=10, meaning the price=7.5

6 0

2 years ago

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The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes

saul85 [17]

Answer:

a)0.08 , b)0.4 , C) i)0.84 , ii)0.56

Step-by-step explanation:

Given data

P(A) = professor arrives on time

P(A) = 0.8

P(B) = Student aarive on time

P(B) = 0.6

According to the question A & B are Independent

P(A∩B) = P(A) . P(B)

Therefore

${A}'$ & ${B}'$ is also independent

${A}'$ = 1-0.8 = 0.2

${B}'$ = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B') (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

$P(\frac{B'}{A})$ = $\frac{P(B'\cap A)}{P(A)}$ = $\frac{0.4\times 0.8}{0.8}$ = 0.4

Part c)

Assume the events are not independent

Given Data

P $(\frac{{A}'}{{B}'})$ = 0.4

= $\frac{P({A}'\cap {B}')}{P({B}')}$ = 0.4

$P$ $({A}'\cap {B}')$ = 0.4 x P $({B}')$

= 0.4 x 0.4 = 0.16

$P({A}'\cap {B}')$ = 0.16

i)

The probability that at least one of them is on time

$P(A\cup B)$ = 1- $P({A}'\cap {B}')$

= 1 - 0.16 = 0.84

ii)The probability that they are both on time

P $(A\cap B)$ = 1 - $P({A}'\cup {B}')$ = 1 - $[P({A}')+P({B}') - P({A}'\cap {B}')]$

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0

2 years ago

At the beginning of the month,Kimberly had $65.78. Since then,she has received three payments of $32.50 from her babysitting job

ivann1987 [24]

Answer:

98.28

Step-by-step explanation:

8 0

2 years ago

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PLZ I NEED HELP UNDERSTANDING THIS SOMEONE PLZ HELP ME

tatuchka [14]

Answer:

90

Step-by-step explanation:

180°-104°=76°( sum of angles A and B)

76°÷2=38°

x=38°

Bcuz it is an isosceles triangle ( a triangle with 2 equal sides). So, angle B and A are equal. thats why 76° must be divided by 2.

180°-104°=76°(angles on a straight line)

180°-76°=104° (sum of angle A and C)

104°÷2=52°

y=52°

it is also an isosceles triangle.

x+y=38+52=90°

7 0

2 years ago

I need help on this question right now

sukhopar [10]

Answer:

96 degrees

Step-by-step explanation:

a

5 0

2 years ago