22.4 L<span>So, if 1 mole occupies 22.4 L, the imediate conclusion is that a bigger number of moles will occupy more than 22.4 L, and a smaller number of moles will occupy less than 22.4 L. In your case, 3 moles of gas will occupy 3 times more volume than 1 mole of gas.</span>
We can use the ideal gas law equation to find the volume occupied by oxygen gas
PV = nRT
where ;
P - pressure - 52.7 kPa
V - volume
n - number of oxygen moles - 12.0 g / 32 g/mol = 0.375 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values in the equation
52 700 Pa x V = 0.375 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
V = 17.6 L
volume of the gas is 17.6 L
Molarity is defined as the number of moles of solute in 1 L of solution
number of NaOH moles present - 0.20 mol
volume of solution - 150 mL
since molarity is taken as number moles of solute in 1000 mL
if 150 mL contains - 0.20 mol
then 1000 mL should contain - 0.20 / 150 x 1000 = 1.33 mol
therefore molarity is 1.33 M
Answer:
your finger becomes negatively charged
Explanation: