If it takes cool air and passes it through the heat source using a fan or blower, the type of heat transfer is convection heat transfer.
<h3>What is heat transfer by convection?</h3>
Convection is the transfer of heat from one place to another due to the movement of fluid.
During heat transfer by convection, cold air replaces hot risen air.
Thus, if it takes cool air and passes it through the heat source using a fan or blower, the type of heat transfer is convection heat transfer.
Learn more about convection here: brainly.com/question/893656
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v^2-u^2=2 x a x d
25^2-0^2=2 x a x 70
625-0=140 x a
625=140a
a=625/140
a=4.46 m/s^2
im not very sure but i think this is how you do this
Let say the height of two balls from the ground is H
now we can use kinematics
now we have
now in the same time ball on the left will cover the horizontal distance between them
![v_x = \frac{d}{ t}[/tex[tex]v_x = \frac{3}{\sqrt{\frac{2H}{g}}}](https://tex.z-dn.net/?f=v_x%20%3D%20%5Cfrac%7Bd%7D%7B%20t%7D%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5Dv_x%20%3D%20%5Cfrac%7B3%7D%7B%5Csqrt%7B%5Cfrac%7B2H%7D%7Bg%7D%7D%7D)
<em>so above is the horizontal speed of the left ball</em>
A ladder 25 feet long is leaning against a house. The base of the ladder is pulled away at a rate of 2 ft/sec.
a.) How fast is the top of the ladder moving down the wall when the base of the ladder is 12 feet from the wall?
Answer:
dy/dt = -1.094ft/sec
Explanation:
Given that:
dz/dt = 0,
dx/dt = 2,
dy/dt = ?
Hence, we have the following
Using Pythagoras theorem
We have 25ft as the hypotenuse, y as the opposite or height of wall, and x as the base of the triangle
X² + y² = z²,
12² + y² = 25²,
y² = 25² - 12²
y = √481
Therefore, we have the following:
2x dx/dt + 2y dy/dt,
= 2z dz/dt,
= 12 (2) √481 dy/dt,
= √481 dy/dt = -24,
= dy/dt = -1.094ft/sec
Therefore, final answer is -1.094ft/sec
