Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2.
Answer:
The mass of the star is, M = 5.9567x10³⁰ Kg
Explanation:
Given
The orbital period of the planet, T = 0.76 year
= 2.3967x10⁷ seconds
The distance between planet and sun, R+h = 1.2 a.u
= 1.795 x 10¹¹ meters
The orbital period of the planet is given by the formula
Squaring and solving for M
Substituting the given values in the above equation
M = 5.9567 x 10³⁰ Kg
Hence, the mass of the star the planet is orbiting, M = 5.9567 x 10³⁰ Kg
Answer :
The frictional force on the block from the floor and the block's acceleration are 10.45 N and 0.73 m/s².
Explanation :
Given that,
Mass of block = 3.50
Angle = 30°
Force = 15.0 N
Coefficient of kinetic friction = 0.250
We need to calculate the frictional force
Using formula of frictional force
(II). We need to calculate the block's acceleration
Using newton's second law of motion
Hence, The frictional force on the block from the floor and the block's acceleration are 10.45 N and 0.73 m/s².
It looks like they are all units of measurement:
FOOT - POUND - NEWTON - METER
Answer:
The xylem distributes water and dissolved minerals upward through the plant, from the roots to the leaves. The phloem carries food downward from the leaves to the roots. Xylem cells constitute the major part of a mature woody stem or root.
Explanation:
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