D, it decreases by 6 every time while the others are multiplied by number
To factor x²-2x-4, you are looking to answer three questions.
1) What pair of numbers multiplies to 4?
2) What pair of numbers multiplies to 1?
3) Do these pairs when multiplied together, add/subtract to the middle term?
To answer (1), our pairs are 2 and 2, 4 and 1. Since there's a negative with 4 at the end (from question one), the signs will be opposite.
To answer (2), only pair multiplies to 1 - 1 and 1. Let's try both pairs from 1.
(x-4)(x+1) The middle term here is -3x. Nope.
(x-1)(x+4). The middle term here is 3x. Nope.
(x-2)(x+2) The middle term is 0x (or no middle term). Nope.
So x²-2x-4 does not factor.
Answer:
1/12 or 0.083
Step-by-step explanation:
The answer is
B. -2 and 3
Step-by-step explanation :
Given the expression
x²- 5x + 6 = 0
Firstly we need to find two numbers that when multiplied will give us the constant term 6, and when added will give us the 2nd term 5
These numbers are 3 and 2
Substituting 2x +3x for 5x
x²- (2x+3x)+ 6 = 0
x²-2x-3x+6=0
(x²-2x)-(3x+6)=0
Factoring we have
x(x-2)-3(x-2)=0
x-3=0, x-2=0
x=3, x= 2
Answer:
it takes 2 seconds to do one situp
it takes 2 seconds to do one pushup
to do 14 pushups, it takes 28 seconds.
to do 12 situps it takes 24 seconds
to do 12 pushups, it takes 24 seconds
BRAINLIEST PLEASE!
hope this helps :)
Step-by-step explanation:
14x + 12y = 52
12x + 12y = 48
^^^ this is an inequality that we can make.
x stands for pushups
y stands for situps
if we subtract the second equation from the first, we get
2x = 4
x = 2
now we can place x in one of the equations to solve for y
12(2)+12y=48
24 + 12y = 48
12y = 24
y = 2