Answer: 12.78ml
Explanation:
Given that:
Volume of KOH Vb = ?
Concentration of KOH Cb = 0.149 m
Volume of HBr Va = 17.0 ml
Concentration of HBr Ca = 0.112 m
The equation is as follows
HBr(aq) + KOH(aq) --> KBr(aq) + H2O(l)
and the mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; while Nb, number of moles of KOH is 1)
Then, to get the volume of a 0.149 m potassium hydroxide solution Vb, apply the formula (Ca x Va)/(Cb x Vb) = Na/Nb
(0.112 x 17.0)/(0.149 x Vb) = 1/1
(1.904)/(0.149Vb) = 1/1
cross multiply
1.904 x 1 = 0.149Vb x 1
1.904 = 0.149Vb
divide both sides by 0.149
1.904/0.149 = 0.149Vb/0.149
12.78ml = Vb
Thus, 12.78 ml of potassium hydroxide solution is required.
<span>A. The nucleus can be either positively charged or neutral.
The nucleus is located at the center of an atom wherein it contains the protons and the neutrons.</span>
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This is bob. If you brainliest him. He will reward you with a certain script.
Your answer is the last option, the explosion of fireworks. This is because all of the other options are physical changes because they don't change the substance, they only affect it in some way. However the explosion of a firework clearly changes a substance inside the initial 'rocket' into fireworks.
I hope this helps!
Answer:
E. Substance A will be the limiting reactant.
Explanation:
Below is a generic equation for a reaction.
2A + 3B → C + 3DA
According to the balanced equation, the theoretical molar ratio of A to B is 2:3, that is, 2 moles of A react with 3 moles of B.
<em>If I mix 2 units of A, with 6 units of B, which of the following is true?</em>
<em>A. There would be no reaction.</em> FALSE. The reaction will occur until the limiting reactant is over
<em>B. Both reactants will fully react.</em> FALSE.
<em>C. Not enough information given.</em> FALSE.
<em>D. Substance B will be the limiting reactant.</em> FALSE. Substance B will be the reactant in excess because there are 6 moles and only 3 moles are required.
<em>E. Substance A will be the limiting reactant.</em> TRUE.