Answer:
C. Yes, if each sample contains 6.02 x 10²³ atoms.
Explanation:
It is possible for each sample to contain 1 mole of each sample if and only if each of the sample if made up of 6.02 x 10²³ atoms.
6.02 x 10²³ atoms is the Avogadro's number. This number is equivalent to a mole of a substance.
- If the amount of matter in the given substance is at least one mole, it is possible that they are made up of one mole each of each substance.
- If they contain lesser amount of atoms, then it is not up to one mole of substance.
- But if it is greater, then, we can have even more than one mole of substance.
A mole is simply a unit of measurement and it is equivalent to 6.02 x 10²³ atoms.
Answer:
0.62 N
Explanation:
first of all: 3.0 s = 0.05 m
Let ? be the work that brakes do at 3.0s
24 m ----> 299 N
0.05 m ---->?
? = (0.05 m x 299 N)/ 24
? = (14.95)/ 24
? = 0.622 N
Answer : The value of is -49.6 kJ/mol
Explanation :
First we have to calculate the reaction quotient.
Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
The given balanced chemical reaction is,
The expression for reaction quotient will be :
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Given:
= 5.0 mM
= 0.60 mM
= 5.0 mM
Now put all the given values in this expression, we get
Now we have to calculate the value of .
The formula used for is:
............(1)
where,
= Gibbs free energy for the reaction = ?
= standard Gibbs free energy = -30.5 kJ/mol
R = gas constant =
T = temperature =
Q = reaction quotient =
Now put all the given values in the above formula 1, we get:
Therefore, the value of is -49.6 kJ/mol
Molality is defined as the number of moles of solute dissolved in 1 kg of solvent.
To calculate molality, we need to calculate the number of moles of CaCl₂.
Mass of CaCl₂ - 5.0 g
Molar mass of CaCl₂ - 111 g/mol
The number of moles of CaCl₂ - 5.0 g / 111 g/mol = 0.045 mol
we need to then calculate the number of moles in 1 kg solvent.
number of CaCl₂ moles in 500 g water - 0.045 mol
Therefore number of moles in 1 kg water - 0.045 mol / 500g x 1000 g = 0.090 mol
Molality of CaCl₂ - 0.090 mol/kg