The following is the correct way to show the product for 0.386 × 6.1: True False

What is the answer to this equation t+t+t=12

OLEGan [10]

Answer:

t = 4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Combining Like Terms

Step-by-step explanation:

Step 1: Define equation

t + t + t = 12

Step 2: Solve for t

Combine like terms (t): 3t = 12
Divide 3 on both sides: t = 4

Step 3: Check

Plug in t into the original equation to verify it's a solution.

Substitute in t: 4 + 4 + 4 = 12
Add: 8 + 4 = 12
Add: 12 = 12

Here we see that 12 does indeed equal 12.

∴ t = 4 is a solution of the equation.

3 0

2 years ago

Bob Nale is the owner of Nale's Texaco GasTown. Bob would like to estimate the mean number of litres (L) of gasoline sold to his

Fudgin [204]

Answer:

a

The point estimate of the population mean is $\= x = 56$

b

The 80% confidence level is $50.57 < \mu < 61.43$

c

There is 80% confidence that the true population mean lies within the confidence interval.

Step-by-step explanation:

From the question we are told that

The sample size is n = 18

The standard deviation is $\sigma = 18 \ L$

The sample mean is $\= x = 56$

Generally the point estimate of the population mean is equivalent to the sample mean whose value is $\= x = 56$

Given that the confidence interval is 80% then the level of significance is mathematically represented as

$\alpha = 100 - 80$

$\alpha = 20 \%$

$\alpha = 0.20$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

The value is $Z_{\frac{ \alpha }{2} } = 1.28$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.28 * \frac{18 }{\sqrt{18} }$

=> $E = 5.43$

Generally the 80% confidence interval is mathematically represented as

$\= x - E < \mu < \= x + E$

=> $56 - 5.43 < \mu < 56 + 5.43$

=> $50.57 < \mu < 61.43$

The interpretation is that there is 80% confidence that the true population mean lies within the limit

3 0

2 years ago

A charter airline finds that on its Saturday flights from Philadelphia to London, all 120 seats will be sold if the ticket price

Nataliya [291]

Answer:

a) $P=3(120-s)+200$

b) $215 \leq P \leq 290$

Step-by-step explanation:

For this case we can use a linear model to solve the problem.

s) Create an equation to express the increase on the price tickets and the number of seats sold

$s$ number of seats, if w analyze the info given the number of seats after increase the price is given by $120-s$ .

And let P the price for the ticket. So after the increase in ticket price the expression for the increase is P-200.

We have an additional info, for each increase of $3 the number of setas decrease 1. And the equation that gives to us the price change in terms of the increase of price is:

$P-200=3(120-s)$

So then our linear equation is given by:

$P=3(120-s)+200$

b) Over a certain period, the number of seats sold for this flight ranged between 90 and 115. What was the corresponding range of ticket prices?

So for this case we just need to replace the limits into the linear equation and see what we got:

$P_L=3(120-90)+200=290$

$P_U=3(120-115)+200=215$

So the corresponding range of ticket prices is:

$215 \leq P \leq 290$

4 0

2 years ago

at best buy a flat screen television with a regular price of 1,790 was reduced by $395 . Assuming 800 customers purchased the te

Margaret [11]

You have to do $1,790 reduced (decreased) by $395 times 800 and your answer is $1166,000

5 0

2 years ago

The mass of the sun is 2.13525×1030 kilograms. The mass of Mercury is 3.285×1023 kilograms. How many times greater is the mass o

Helga [31]

6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.

8 0

2 years ago

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