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suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z =
=
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Answer:
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Step-by-step explanation:
hero ko
Answer:
21.53 in of fabric on headbands
7.67 in of fabric on wristbands.
Step-by-step explanation:
Step one:
given data
the total amount of person players plus coaches= 27+4= 31
for each person, she uses = 667.43/31= 21.53 in of fabric on headbands
She also uses 237.87inches of fabric on wristbands for just the players
For each player, she will use= 237.87/31= 7.67 in of fabric
Hence for each player, she used
21.53 in of fabric on headbands
7.67 in of fabric on wristbands
-16t^2 + 25t + 8 = 10
-16t^2 + 25t - 2 = 0
t = 1.48 seconds