Answer:
Step-by-step explanation:
The parabola with vertex at point (h,k) is described by the following model:
The equation which satisfies the conditions described above:
The two points are evaluated herein:
x = -6
x = -2
The equation of the translated function is .
Answer:
A. 2.25
Step-by-step explanation:
-3x + 10 = 5x - 8 (Given)
10 = 8x - 8 (Added 3x on both sides)
18 = 8x (Added 8 on both sides)
2.25 = x (Divided 8 on both sides)
Answer:
Step-by-step explanation:
11) First write in decreasing exponential terms and fill in blanks with zeros.
Our goal is to eliminate all term in the dividend by subtraction
________________
2v - 2 | 2v³ - 16v² + 0v + 13
we see that 2v needs to be multiplied by 1v² to eliminate the first term
<u> v² </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v²
multiply your estimate by your divisor and subtract from the dividend.
bring down the next term and repeat.
<u> v² -7v </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v² + 0v
<u>-(-14v² + 14v)</u>
- 14v
repeat again
<u />
<u> v² - 7v - 7 </u>
2v - 2 | 2v³ - 16v² + 0v + 13
<u>- (2v³ - 2v²)</u>
0 - 14v² + 0v
<u>-(-14v² + 14v)</u>
- 14v + 13
<u>-(-14v + 14)</u>
-1
and remainder gets put over the divisor and appended
v² - 7v - 7 - 1/(2v - 2)
13) Same process
<u> </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u> 8a² </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
<u> 8a² - 4a </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
-(-<u>20a² - 4a)</u>
-35a - 5
<u> 8a² - 4a - 7 </u>
5a + 1 | 40a³ - 12a² - 39a - 5
<u>-(40a³ + 8a²)</u>
-20a² - 39a
-(<u>20a² - 4a)</u>
-35a - 5
-<u>(-35a - 7)</u>
2
8a² - 4a - 7 + 2/(5a + 1)
Answer:
-> See attached
115.893 meters²
Step-by-step explanation:
See attached for my sketch.
Area for a rectangle is A = L * W:
9.78 meters * 11.85 meters = 115.893 meters²
The <em>correct answer</em> is:
The mean for July is smaller than the median; and
the mean for August is larger than the median.
Explanation:
A distribution with a positive skew would have a longer whisker in the positive direction than in the negative direction. A larger mean than median would also indicate a positive skew.
Alternatively, a distribution with a negative skew would have a longer whisker in the negative direction than in the positive direction. A smaller mean than median would also indicate a negative skew.
The whisker in the negative direction for July is longer than the whisker in the positive direction. This indicates a negative skew.
The whisker in the positive direction for August is longer than the whisker in the negative direction. This indicates a positive skew.