Answer:
y = 5x/2 + 2
Step-by-step explanation:
We know the equation for slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Since we have the coordinates of one point on this line and the slope, we can substitute that in and find b first:
y = mx + b
-8 = 5/2(-4) + b
-8 = -10 + b
b = 2
So we can use the slope and this y intercept we found to plug back into the equation:
y = mx + b
y = 5x/2 + 2
R S + 14(S) R=6 S=1/4
(6)(1/4) + 14(1/4)
1.5 + 14(1/4)
1.5 + 3.5
5
Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
41 students
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304: total students
17: riding in car
7: number of buses
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304 - 17 = 287
287 divided by 7 = 41