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2 years ago

The table represents the height of a rock that is dropped, h(t), in meters, after t seconds.

Mathematics

2 answers:

laiz [17]2 years ago

5 0

Answer:

<h2>The rock hits the ground between 2 and 2.5 seconds.</h2>

Step-by-step explanation:

The given table is:

t h(t)

0 20

0.5 18.8

1 15.1

1.5 9

2 0.4

2.5 -10.6

3 -24.1

The ground level is when h(t) = 0, which is between 0.4 and -10.6, because in that interval is included the zero. So, the problem is asking when does the rock hit the ground, referring to time. We just have to look for t-values for 0.4 and -10.6.

<em>Therefore, the rock hits the ground between 2 and 2.5 seconds.</em>

harina [27]2 years ago

4 0

Answer:

The rock hits the ground between 2

seconds and 2.5

seconds after it is dropped.

Step-by-step explanation:

At 2 seconds, the height of the rock is 0.4 meters, and at 2.5 seconds the height of the rock is -10.6 meters. Therefore, the rock hit the ground, or 0 meters, between those times.

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2 years ago

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2 years ago

8.5+4(1-2.5k)=24.5 round to the nearest hundredth

frosja888 [35]

Hi there!

Your question:

8.5 + 49(1-2.5k)=24.5

My answer:

8.5 + 4(1-2.5k) = 24.5 >>>>>>> first, you have to distribute

8.5 + 4 - 10k = 24.5 >>>>>>>> now, we are going to combine like terms.

12.5 - 10k = 24.5 >>>>>> now, we are going to subtract 12.5 on both sides

-10k = 12 >>>>>>>>> finally, divide -10 on both sides

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Hope this helps you!

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2 years ago

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