Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
Answer:
B
Step-by-step explanation:
3.2 * 10⁷ + 6.4 * 10⁷
= 10⁷ * (3.2 + 6.4)
= 10⁷ * 9.6
= 9.6 * 10⁷
Answer:
930 dollars
Step-by-step explanation:
Let software programs = S
Video game = V
Given that a company makes a profit of $7 per software program that is, 7S and $8 per video game that is, 8V. The company can produce at most 90 software programs and at most 80 video games per week. Since the Total production cannot exceed 120 items per week.
How many items of each kind should be produced per week in order to maximize the profit?
The to get profit P
P = 7S + 8V
Since the profit on video game is higher, we will give maximum production to video game. Therefore,
P = (30 × 7) + ( 8 × 90)
P = 210 + 720
P = 930 dollars
Answer:D
Step-by-stepA explanation: if you simply the fraction by 4/15. The answer is 0.26
The solution is equal to both numbers.
Normal-travel DATA:
distance = 240 km
rate = x km/h
time = d/r
= 240/x hrs
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Bad weather DATA:
distance = 240 km
rate = (x-20) km/h
time = 240/(x-20) hrs
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Bad time - normal time = 2 hrs
240/(x-20) - 240/x = 2
120/(x-20) - 120/x = 1
120x -120(x-20) = x(x-20)
20 = x^2 -20x
x^2 - 20x - 20 = 0
x = [20 +- sqrt(20^2 - 4*1*-20)]/2
x = [20 +- sqrt(480)]/2
x = [20 +- 4sqrt(30)]/2
x = 10 +- 2sqrt(30)