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2 years ago

Which is not a valid way to determine the perimeter of a rectangle with side lengths of 18 inches and 22 inches?

Mathematics

1 answer:

Andreyy892 years ago

5 0

Answer:

P = 2(18) + 22

Step-by-step explanation:

The formula for the perimeter for a rectangle is P = 2(l + w). Take this equation and expand to find its equivalents.

P = 2(l + w) This is P = 2(18 + 22)

P = 2l + 2w This is P = 2(18) + 2(22)

P = l + l + w + w This is P = 18 + 22 + 18 + 22

It is only P = 2(18) + 22 that is not equal to the others. It does not have the fourth side of 22.

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Geomtry plz help 15 points

VladimirAG [237]

Answer:

m∠E=57°

Step-by-step explanation:

∠FDE=∠FED=(4x+1)° (base angles of isos triangle)

2(4x+1)+(5x-4)=180 (angle sum of triangle)

8x+2+5x-4=180

13x-2=180

13x=180+2

=182

x=182÷13

=14

Hence, m∠E = (4x+1)°

= [4(14)+1]°

= (56+1)°

= 57°

5 0

1 year ago

Read 2 more answers

Fiona wrote the linear equation y = 2/5 x – 5. When Henry wrote his equation, they discovered that his equation had all the same

Hoochie [10]

we have

$y=\frac{2}{5}x-5$

Let's Isolate the variable y in each of the cases and then compare with Fiona's equation to determine the solution of the problem

case A) $x-\frac{5}{4}y= \frac{25}{4}$

Multiply by $4$ both sides

$4x-5y= 25$

$5y=4x-25$

Divide by $5$ both sides

$y=\frac{4}{5}x-5$

therefore

the case A) is not equal to Fiona's equation

case B) $x-\frac{5}{2}y= \frac{25}{4}$

Multiply by $4$ both sides

$4x-10y= 25$

$10y=4x-25$

Divide by $10$ both sides

$y=\frac{2}{5}x-2.5$

therefore

the case B) is not equal to Fiona's equation

case C) $x-\frac{5}{4}y= \frac{25}{2}$

Multiply by $4$ both sides

$4x-5y= 50$

$5y=4x-50$

Divide by $5$ both sides

$y=\frac{4}{5}x-10$

therefore

the case C) is not equal to Fiona's equation

case D) $x-\frac{5}{2}y= \frac{25}{2}$

Multiply by $2$ both sides

$2x-5y= 25$

$5y=2x-25$

Divide by $5$ both sides

$y=\frac{2}{5}x-5$

therefore

the case D) is equal to Fiona's equation

<u>the answer is</u>

$x-\frac{5}{2}y= \frac{25}{2}$

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