Hello there!
Knowing that the vertex form of the quadratic equation is
y=a(x-h)^2+k where (h,k) represents the vertex, and the a value represents the leading coefficient of the quadratic equation in standard form, first plug in your known values (your given coordinate point can be plugged into the x and y values, and your given vertex can be plugged into h and k):
-4=a(0-10)^2-9
Because your a value is still unknown, you can use your given values in the equation to solve for a:
-4=a(-10)^2-9
-4=100a-9
100a=5
a=1/20
Now that you have your a value, you can plug it into your vertex form as well as your vertex values to get that your equation in vertex form is:
y=1/20(x-10)^2-9
Answer:
the answer is x=e⁴........
45 should be the answer for that specific question.
Answer:
The Graph Shifts 4 units up
Step-by-step explanation:
Okay so, when you add four to a graph in this manner we have to look at the equation as a whole. f(x)=mx+b + 4. By adding four we are changing the y-intercept and shifting it up four. This will cause the entire graph to shift upwards four spaces.
