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2 years ago

10

When using the inspection method, which number would you add to (and subtract from) the constant term of the numerator in this e

xpression so the polynomial in the numerator will have (x+4) as a factor?
x^2+7x+15/x+4

1 answer:

olasank [31]2 years ago

3 0

If i were you, i would add one to 7x and fifteen. this gives you x^2+8x+16, a perfect square of x+4.

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-7b< -35<br> =less than or equal two

timama [110]

Answer:

b>5

=greater than or equal too

Step-by-step explanation:

divide -35 by -5, and since you are dividing by a negative, the sign flips

6 0

2 years ago

How many bucketloads would it take to bucket out the world’s oceans? Write your answer in scientific notation.

kodGreya [7K]

Answer: $7\times10^{19} buckets$

Step-by-step explanation:

Given: A cubic kilometer= $10^{15}$ cubic centimeters

The volume of world’s oceans= $1.4\times10^{9}$ cubic kilometers of water.

⇒ The volume of world’s oceans= $1.4\times10^{9}\times10^{15}$ cubic centimeters of water.

Volume of a bucket = 20,000 cubic centimeters of water.

The number of bucket-loads would it take to bucket out the world’s oceans

$n=\frac{\text{volume of ocean}}{\text{volume of bucket}}=\frac{1.4\times10^{9}\times10^{15}}{20000}$

$\Rightarrow\ n=\frac{1.4\times10^{9+15}}{0.2\times10^5}......[a^n\times a^m=a^{m+n}]\\\Rightarrow\ n=7\times10^{24-5}.....[\frac{a^m}{a^n}=a^{m-n}]\\\Rightyarrow\ n=7\times10^{19}$

hence, $7\times10^{19}$ bucketloads would it take to bucket out the world’s oceans.

5 0

2 years ago

3/5 -(-2/7) i need the value of the expression and work to show

trapecia [35]

The answer is 31/35 :)

7 0

2 years ago

The length of a rectangle is 5 in longer than its width.

NeTakaya

Answer:

Length = 21

Width = 16

Step-by-step explanation:

We know that the formula for perimeter is:

P=2W+2L

And we also know that:

L=W+5

So then we put all that we know in the formula:

74=2W+2(W+5)

Now we expand the brackets and do some algebra:

74=4W+10 (-10)

64=4W (÷4)

16=W

Now that we know the width we can pop that into the length equation:

L=16+5

L=21

5 0

2 years ago

The amount of time, in minutes, that a woman must wait for a cab is uniformly distributed between zero and 12 minutes, inclusive

murzikaleks [220]

Answer:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

Step-by-step explanation:

Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:

$X \sim Unif (a=0, b =12)$

And we want to find the following probability:

$P(X$

And for this case we can use the cumulative distribution function given by:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

7 0

2 years ago