For this question, lets apply Avagadro's law
when Pressure and temperature are constant, the volume occupied is directly proportional to the number of moles of gases.
where V-volume, n-number of moles and k - constant
Therefore at 2 instances
where V1 and n1 are for 1st instance
and V2 and n2 are for 2nd instance
therefore
V1 = 2.4 L
n1 = 3.7 mol
n2 = 3.7 + 1.6 = 5.3 mol
since more He moles are added at the 2nd instance its the sum of the moles.
V2 needs to be calculated
V2 = 2.4 x 5.3 / 3.7
= 3.4 L
Answer is 1st option 3.4 L
Answer: The approximate pressure of the gas after it is heated to 278 K is 0.468 atm.
Explanation:
Given: = 178 K, = 0.3 atm
= 278 K, = ?
According to Gay Lussac law, at constant volume the pressure of a gas is directly proportional to the temperature.
Formula used to calculate the pressure is as follows.
Substitute the values into above formula is as follows.
Thus, we can conclude that the approximate pressure of the gas after it is heated to 278 K is 0.468 atm.
False. For example, changing climates will mean that some areas that experience harsh weather will soon being to experience milder weather. :)
Answer : The volume of hydrogen gas at STP is 4550 L.
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 100.0 atm
= final pressure of gas at STP = 1 atm
= initial volume of gas = 50.0 L
= final volume of gas at STP = ?
= initial temperature of gas =
= final temperature of gas at STP =
Now put all the given values in the above equation, we get:
Therefore, the volume of hydrogen gas at STP is 4550 L.
<span>PV = nRT
(4000 Torr)(5 L) = n (62.4 Torr-L/mol-K)(296K)
n = 1.08 moles
28 g/mol, 1.08 moles = 30.3 grams
your answer is
C.30.3 g</span>