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Sergio039 [100]

2 years ago

7

Using Hooke's law, F s p r i n g = k Δ x , find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 new

ton force is applied to it.
1/2cm

2 cm

4 cm

8 cm

2 answers:

irakobra [83]2 years ago

6 0

1/2cm

just took the test and this is the right answer

ki77a [65]2 years ago

3 0

I think it is the first option 1/2 cm.

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The average kinetic energy of the atoms that make up a substance which is changing from a liquid to a solid is _____________.dec

Zepler [3.9K]

Here is your answer:

Your answer is A decreasing.

Reason: That's because when your turning into a solid your not moving and kinetic energy is the around of movement an object is moving.

Your answer is A.

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2 years ago

CH3(CH2)50CH3<br><br> How many atoms

ahrayia [7]

24

Explanation:

An atom is the smallest indivisible particle of any matter. Atoms are distinct and distinguishable from one another and are called elements:

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There are 3 different kinds of atoms in the compound above called

elements

Carbon

Hydrogen

Oxygen

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2 years ago

A rock is found to contain 2.2 grams of uranium-235, a radioactive isotope. If the rock has undergone 2.75 half-lives, what was

Verizon [17]

Answer:

=14.8 grams

Explanation:

The remaining amount is normally calculated using the formula:

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Remaining mass= 2.2 grams

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2 years ago

Use the Henderson-Hasselbalch equation, eq. (3), to calculate the pH expected for a buffer solution prepared from this acid and

notka56 [123]

Answer:

$pH=4.56$

Explanation:

Hello there!

In this case, given the Henderson-Hasselbach equation, it is possible for us to compute the pH by firstly computing the concentration of the acid and the conjugate base; for this purpose we assume that the volume of the total solution is 0.025 L and the molar mass of the sodium base is 234 - 1 + 23 = 256 g/mol as one H is replaced by the Na:

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And the concentrations are:

$[acid]=0.000855mol/0.025L=0.0342M$

$[base]=0.000781mol/0.025L=0.0312M$

Then, considering that the Ka of this acid is 2.5x10⁻⁵, we obtain for the pH:

$pH=-log(2.5x10^{-5})+log(\frac{0.0312M}{0.0342M} )\\\\pH=4.60-0.04\\\\pH=4.56$

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