Speed = (frequency)x(wavelength).
Frequency = 6 Hz
Wavelength = 9mm = 0.009m.
Speed = (6 Hz) x (0.009m) = 0.054 m/s or 54 mm/sec.
The solution you should use is Hooke's law: F=-kx
It should have the same signs because they repel due to the stretch of the spring.
a. Since there is a constant energy within the spring, then Hooke's law will determine the possible algebraic signs. The solution should be
<span>F = kx
270 N/m x 0.38 m = 102.6 N
</span>
b. Then use Coulomb's law; F=kq1q2/r^2 to find the charges produced in the force.
Answer:
650 km/hr
Explanation:
Draw a right triangle from (0.0) (Point A) down 30 degrees and to the right for a length of 750 (Point B). Then draw a line from B up to the x axis to make a right angle (Point C). Use the cosine function to find line AC, the vector portion of AB that lies of the x (East) axis. Cosine(30)= Adjacent/Hypotenuse.
Cos(30) = AC/750
750*(cos(30)) = AC
AC = 649.5 km/hr
Answer:
15.6m/s
Explanation:
V1= because the derivate of the position is the velocity
V1=12t+3
V2=20+-8t because the integral of the acceleration is the velocity
V2=
V1=V2 to see when the velocities of particles match
12t+3=20-4t^2
4t^2+12t-17=0 we resolve this with
and we take the positif root
t=1.05 sec
if we evaluate the velocity (V1 or V2) the result is 15.6m/s