The example of the scientific practice is missing here but it should always involve the application of the scientific method.
<h3>What is the scientific method?</h3>
The scientific method is a series of steps by which researchers can collect empirical evidence that enables them to test hypotheses and generate scientific theories.
The scientific method starts with the observation of a given phenomenon from the real world, which then enables the raising of a question that in turn enables the formulation of a plausible explanation called hypothesis.
In conclusion, the example of the scientific practice is missing here but it should always involve the application of the scientific method.
Learn more about the scientific method here:
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Answer:
According to Newton's Second Law of Motion :
Where,
F = Force Applied
m = Mass of the object
a = Acceleration
Now, we will use this law to solve this question.
Given :
Acceleration or a = 15.3 m/s²
Force = 44 N
Mass = ?
Substitute, the given values in the formula.
F = ma
⇒ m = F/a
m = 44/15.3
<u>m = 2.9 kg</u>
<span>So we want to know why is there a difference between the force of gravity on the Moon and the force of gravity of the Earth. So the gravitational force between two objects depends on the masses of both objects. That can be seen from Newtons universal law of gravity. F=G*m1*m2*(1/r^2). So lets say we are holding an object of mass m=1kg on a height r=1m on the Moon and we are holding the same object on the Earth also on the same height of r=1m. The Gravitational force on the Earth will be Fg=G*M*m*(r^2) where M is the mass of the Earth. The force between the moon and that object will be Fg=G*n*m*(r^2), where n is the mass of the moon. Since mass of the Moon is much smaller than mass of the Earth, The gravitational force between the Moon and that body will be almost 6 times smaller than the gravitational force between the Earth and that body. So the correct answer is B. </span>
Answer:
86.51° North of West or 273.49°
Explanation:
Let V' = velocity of boat relative to the earth, v = velocity of boat relative to water and V = velocity of water.
Now, by vector addition V' = V + v'.
Since v' = 6.10 m/s in the north direction, v' = (6.10 m/s)j and V = 100 m/s in the east direction, V = (100 m/s)i. So that
V' = V + v'
V' = (100 m/s)i + (6.10 m/s)j
So, we find the direction,Ф the boat must steer to from the components of V'.
So tanФ = 6.10 m/s ÷ 100 m/s
tanФ = 0.061
Ф = tan⁻¹(0.061) = 3.49°
So, the angle from the north is thus 90° - 3.49° = 86.51° North of West or 270° + 3.49° = 273.49°
