301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.
Answer:
A, C
Step-by-step explanation:
$115.45 This should be the correct answer. Hope this help need brainlest.
1. 50 + 20x = 240
2. 85% so more than 75%
3. 25.9% so about 26%
Hope this helps and please consider marking branliest if this helped you
Answer:
66%
bcz out of 3 stuff in 100% is 66%