Step-by-step explanation:
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How many solutions are possible for the equation 5(x-3)=7x-2(x+)1
1 answer:
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Answer:
Second statement is true.
The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.
Step-by-step explanation:
for first part of statement
The lengths 7, 40 and 41 can not be sides of a right triangle.
If the square of long side is equal to the sum of square of other two sides
then the given length can be sides of a right triangle.
Check the given length by Pythagoras Theorem.
----------(1)
Let and
and
Put all the value in equation 1.
Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.
for second part of statement.
The lengths 12, 16, and 20 can be sides of a right triangle.
Check the given length by Pythagoras Theorem.
Let and
and
Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.
Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.