Supplementary angle of 80

This table shows temperatures in an Arctic city during

ioda

According to the temperature changes, it is found that:

On Tuesday, the temperature at Noon was of -28.5 ºF.

On Wednesday, the temperature at Midnight was of -5.5 ºF.

On Thursday, the change was of -11.8 ºF.

On Friday, the temperature at Noon was of -4.5 ºF.

<h3>What is the temperature change?</h3>

The temperature change during a period is given by the <u>temperature at the end of the period subtracted by the temperature at the start of the period</u>.

On Tuesday:

At the start of the period, the temperature was of -17.5 ºF.

The change was of -11 ºF.

Hence:

$-11 = T_N - T_M$

$-11 = T_N + 17.5$

$T_N = -28.5$

On Tuesday, the temperature at Noon was of -28.5 ºF.

On Wednesday:

At the end of the period, the temperature was of 10 ºF.

The change was of 15.5 ºF.

Hence:

$15.5 = 10 - T_M$

$T_M = -5.5$

On Wednesday, the temperature at Midnight was of -5.5 ºF.

On Thursday:

At the end of the period, the temperature was of -24 ºF.

At the start of the period, the temperature was of -12.2 ºF.

Hence:

$C = -24 - (-12.2) = -24 + 12.2 = -11.8$

On Thursday, the change was of -11.8 ºF.

On Friday:

At the start of the period, the temperature was of -21.8 ºF.

The change was of 17.3 ºF.

Hence:

$17.3 = T_N - T_M$

$17.3 = T_N + 21.8$

$T_M = -4.5$

On Friday, the temperature at Noon was of -4.5 ºF.

You can learn more about change at brainly.com/question/24313700

8 0

2 years ago

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft and on the other three s

makvit [3.9K]

Answer:

The dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

Step-by-step explanation:

Let the length of garden be x

Let the breadth of garden be y

Area of Rectangular garden = $Length \times Breadth = xy$

We are given that the area of the garden is 122 square feet

So, $xy=122$ ---A

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft

So, cost of brick along length x = 20 x

On the other three sides by a metal fence costing $10/ft.

So, Other three side s = x+2y

So, cost of brick along the other three sides= 10(x+2y)

So, Total cost = 20x+10(x+2y)=20x+10x+20y=30x+20y

Total cost = 30x+20y

Substitute the value of y from A

Total cost = $30x+20(\frac{122}{x})$

Total cost = $\frac{2440}{x}+30x$

Now take the derivative to minimize the cost

$f(x)=\frac{2440}{x}+30x$

$f'(x)=-\frac{2440}{x^2}+30$

Equate it equal to 0

$0=-\frac{2440}{x^2}+30$

$\frac{2440}{x^2}=30$

$\sqrt{\frac{2440}{30}}=x$

$9.018 =x$

Now check whether it is minimum or not

take second derivative

$f'(x)=-\frac{2440}{x^2}+30$

$f''(x)=-(-2)\frac{2440}{x^3}$

Substitute the value of x

$f''(x)=-(-2)\frac{2440}{(9.018)^3}$

$f''(x)=6.6540$

Since it is positive ,So the x is minimum

Now find y

Substitute the value of x in A

$(9.018)y=122$

$y=\frac{122}{9.018}$

$y=13.528$

Hence the dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

4 0

2 years ago

Which is bigger 5t 2 in or 61 in?<br><br> correct=brainliest

nikitadnepr [17]

Answer:

5 ft 2 in

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

I NEED HELP!!! PLEASE HELP!!! FIRST TO ANSWER GETS 50 POINTS AND BRAINLIEST ANSWER!!! HEEELLPPPP!!!! Find the distance between p

daser333 [38]

Answer:

8.6 to the nearest tenth.

Step-by-step explanation:

Using the distance formula d = √ [(y2 - y1)^2 + (x2 - x1)^2] where (x1, y1) and (x2, y2) are the two endpoints.

= √ (4 - -3)^2 + (-3-2)^2

= √(49 + 25)

= 8.60

6 0

2 years ago

The length of the hypotenuse of a right triangle is 16 inches. If the length of one leg is 5 inches, what is the approximate len

Musya8 [376]

Answer:

15.2 inches

Step-by-step explanation:

a^2 + b ^2= c^2

5^2 + b ^2=16^2

b ^2=256 - 25

√b ^2=√231

b= 15.2 inches

7 0

2 years ago