A sample of a compound contains 60.0 g C and 5.05 g H.
divide by molar mass of C(12) and H(1) to get molar ratio
C: 60/12=5 and H: 5/1=5
so C:H=5:5=1:1
total molar mass=78
divide by 1C+1H to find the formula: 78/(12+1)=78/13=6
compound is C6H6
Given:
M = 0.0150 mol/L HF solution
T = 26°C = 299.15 K
π = 0.449 atm
Required:
percent ionization
Solution:
First, we get the van't Hoff factor using this equation:
π = i MRT
0.449 atm = i (0.0150 mol/L) (0.08206 L atm / mol K) (299.15 K)
i = 1.219367
Next, calculate the concentration of the ions and the acid.
We let x = [H+] = [F-]
[HF] = 0.0150 - x
Adding all the concentration and equating to iM
x +x + 0.0150 - x = <span>1.219367 (0.0150)
x = 3.2905 x 10^-3
percent dissociation = (x/M) (100) = (3.2905 x 10-3/0.0150) (100) = 21.94%
Also,
percent dissociation = (i -1) (100) = (</span><span>1.219367 * 1) (100) = 21.94%</span>
Answer:
Oxygen has 2 energy levels
Explanation:
Could you please describe the question?
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We are going to use table salt, NaCl as an example.
(s) = solid, eg the salt you put on your food is a crystalline solid.
(l) = liquid, if you melt salt it take on a liquid form
(g) = gaseous, if you put enough energy in the salt will turn into a gas.
(aq) = aqueous, meaning in water or another solvent. If you put some table salt in water and stir it, it will dissolve, the NaCl molecules dont get destroyed but they dissolve becoming part of the liquid.
