Answer:
0.75
0.75>0.723 due to it being greater in the hundreths place
Answer:
x=8
Step-by-step explanation:
3(x-5)=9
3x-15=9
3x-15+15=9+15
3x=24
x=8
Hey there Mejia021274,
1) Independent systems have exactly one solution:
x + y = 1
x - y = 3
x = 2, y = -1
2) Inconsistent systems have no solutions :
5x + y = 6
5x + y = 10
There is no solution as 5x + y cannot be equal to 6 and 10
3) Consistent systems have a lot of solutions:
x+y = 5
<span>2x+2y = 10 </span>
<span>A few solutions to this system are (1,4), (2,3), (3,2), (4,1), (5,0), and so on.
</span>
Hope this helps :))
~Top
Let's go through the choices one by one
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Choice A
If all sides are congruent, then this figure is a rhombus (by definition). If all angles are congruent, then we have a rectangle. Combine the properties of a rhombus with the properties of a rectangle and we have a square.
In terms of "algebra", you can think
rhombus+rectangle = square
Or you can draw out a venn diagram. One circle represents the set of all rhombuses; another circle represents the set of all rectangles. The overlapping region is the set of all squares. The overlapping region is inside both circles at the same time.
So we can rule out choice A. This guarantees we have a square when we want something that isn't a guarantee.
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Choice B
If we had a parallelogram with perpendicular diagonals, then we can prove that we have a rhombus (all four sides congruent). However, we don't know anything about the four angles of this parallelogram. Are they congruent? We don't know. So we can't prove this figure is a rectangle. The best we can say is that it's a rhombus. It may or may not be a rectangle. There isn't enough info about the rectangle & square part.
This is why choice B is the answer. We have some info, but not enough to be guaranteed everytime.
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Choice C
This is a repeat of choice A. Having "all right angles" is the same as saying "all angles congruent". This is because "right angle" is the same as saying "90 degrees". So we can rule out choice C for identical reasons as we did with choice A.
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Choice D
As mentioned before in choice A, if we know that a quadrilateral is a rectangle and a rhombus at the same time, then the figure is also a square. This is always true, so we are guaranteed to have a square. We can cross choice D off the list.
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Once again, the final answer is choice B
Answer:
Step-by-step explanation:
We know that:
Only employees are hired during the first 3 days of the week with equal probability.
2 employees are selected at random.
So:
A. The probability that an employee has been hired on a Monday is:
.
If we call P(A) the probability that 2 employees have been hired on a Monday, then:
B. We now look for the probability that two selected employees have been hired on the same day of the week.
The probability that both are hired on a Monday, for example, we know is . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.
So
.
C. If the probability that two people have been hired on a specific day of the week is 
, then the probability that 7 people have been hired on the same day is:
D. The probability is 
. This number is quite close to zero. Therefore it is an unlikely bastate event.
