All categories

2 years ago

Which best describes the polygon whose vertices in the coordinate plane are (-5,5),(0,5),(0,0),(-5,0)?

2 answers:

7 0

<em>A polygon with those is actually a square, yes, the other answer was right. So if it is a square that means it's only </em><span><em>equiangular</em></span>

valina [46]2 years ago

3 0

The polygon with these points is actually a square. I downloaded graph paper and put the points in the graph and the shape is a perfect square.

You might be interested in

what are 3 online websites I can take pictures on with, without saving to ur device , it stays on that site and its just for u

Schach [20]

Answer:

Webca-mtoy.com webca-mera.io I only know 2

Step-by-step explanation:

5 0

2 years ago

What is 2(x+10)=2(3x-8)

Mrac [35]

Answer:

x=9

Step-by-step explanation:

we can start by using the distributive property

so then

2x+20=6x-16

we now need to move the variables to one side and the numbers to the other

-4x=-36

x=9

3 0

2 years ago

Read 2 more answers

Please assist with this. No links or your account will be banned. Will give brainliest, show steps!!!!!

EastWind [94]

Answer:

$\huge\boxed{\sf 16}$

Step-by-step explanation:

<u>Given expression is:</u>

= 10 + 3(12 ÷ (3x))

Put x = 2 nd use PEDMAS [Parenthesis Exponents Division Multiplication Addition Subtraction "in that order"]

= 10 + 3(12 ÷ (3)(2))

Solve Parenthesis

= 10 + 3(12 ÷ 6)

Now, Divide

= 10 + 3(2)

Now, Multiply

= 10 + 6

Now, Add

= 16

$\rule[225]{225}{2}$

Hope this helped!

5 0

1 year ago

Read 2 more answers

1 3/7 x 2 3/4<br> fraction plz

maksim [4K]

Answer:

$\frac{55}{14}$

Step-by-step explanation:

First, we convert the mixed numbers into improper fractions: $1\frac{3}{7} =\frac{10}{7}$ , and $2\frac{3}{4}=\frac{11}{4}$ . Now, we multiply the fraction using the multiplication rule, $\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}$ : $\frac{10}{7} \times \frac{11}{4} = \frac{110}{28} = \frac{55}{14}$ .

Thus, the product of the two given fractions is 55/14.

7 0

2 years ago

If the function f(x) has a domain of (g,h) and a range of (j,k), then what is the domain and range of g(x) = m(f(x)] + p?

sertanlavr [38]

Answer:

$Dom\{g(x)\} = Dom\{f(x)\} = (g, h)$ .

$Ran \{g(x)\} = (m\cdot j+p,m\cdot k +p)$

Step-by-step explanation:

From Mathematics we remember that the domain of a functions corresponds to the set of values of the independent variable ( $x$ in this case) so that images exist and the range of a function is the set of images.

In this case, we know the domain and range of $f(x)$ and we must find the domain and range of $g(x)$ .

Domain

The domain of $g(x)$ is the domain of $f(x)$ . That is, $Dom\{g(x)\} = Dom\{f(x)\} = (g, h)$ .

Range

We have to define the bounds of the range of $g(x)$ , given that range $f(x)$ is modified by streching and horizontal translation operations:

Lower bound ( $f(x) = j$ )

$g(x) = m\cdot j +p$

Upper bound ( $f(x) = k$ )

$g(x) = m\cdot k +p$

In consequence, the range of $g(x)$ is $Ran \{g(x)\} = (m\cdot j+p,m\cdot k +p)$

3 0

3 years ago