<span>it depends how the interest is calculated, but there's not much of a difference
assuming its continuously compouned, you use this formula: A(t)=Pe^(rt), where A is the final amount, P is the initial investment, r is the interest, and t is the time in years
you want to find t such that A(t)=18,600 so 18,600=1000e^(.0675t)
you need to use logarithm to figure it out, take the natural log of both sides
the following properties will come into use:
ln(a*b)=ln(a)+ln(b)
ln(a^b)=bln(a)
ln(e)=1
taking the natural log
ln(18,600)=ln(1000e^(.0675t))
ln(18,600)=ln(1000)+ln(e^.0675t)
ln(18600)=ln(1000) + .0675t
now solve for t: t= (ln(18600)-ln(1000))/.0675
t=43.31</span>
Answer:
79°
Step-by-step explanation:
Angle one is an alternate exterior angle to the angle that has 79° in it so angle one will equal 79°.
The answer is A. (-2,-3)
You can use your graphing calculator and go to Matrix and edit. Then plug in the values and next, go to rref and find the values.
Answer:
s > 42
Step-by-step explanation: INCOMPLETE QUESTION, PROBLEM STATEMENT DOES NOT GIVE THE MODELING FUNCTION.
I´VE FOUND IN NTERNET PROFIT
p(s) = s² + 9*s - 142
Then we have
s² + 9*s - 142 > 2000
rearrange that inequation
s² + 9*s - 142 > 2000 ⇒ s² + 9*s - 2142 > 0
we complete the expression as a perfect quadratic, with the help of two number that add +9 and multiplying - 2142
Numbers are 51 and - 42
then
factoring that expression as a perfect quadratic
( s + 51 )* ( s - 42 ) > 0
For what have two solution, and we dismiss the negative value since the numbers of shirts could not be negative, we get
s - 42 > 0
s > 42 the solution
