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3 years ago

I need help with these two please

Mathematics

2 answers:

jek_recluse [69]3 years ago

4 0

13. Add 2 on both sides. So you get p/4 =2.8 then multiply by 4 on both sides. This cancels out 4 and leave with p= 11.2

damaskus [11]3 years ago

4 0

16 first substract 15 from both sides then you will get s/8 =12 then multiply both sides by 8 to leave s by it self 12 times 8 is 96 so s=96

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Please help me, thanks.

bixtya [17]

Your expression would be

$(3 {}^{9} - 4) - r$
because of the order of operations this expression is valid to the world problem

3 0

2 years ago

Which inequality represents a number n that is less than or equal to 3 but greater than -2?

Kisachek [45]

-2 < n $\leq$ 3

This inequality basically says "-2 is less than n, which is less than or equal to 3".

Mark as brainliest if this helped! :)

5 0

2 years ago

What is the answer to -6(a+8)

Dafna11 [192]

Answer: -6a-48

Step-by-step explanation:

First -6 goes into a and that turns into -6a and then -6 goes into 8 and that turns into -48 so ur answer would be: -6a-48

ur welcome

8 0

2 years ago

PLEASE HELP!!!

tatyana61 [14]

Answer: The equation is y= -2x -4

Step-by-step explanation:

The slope intercept form is like y=mx+b so we know the slope which is m but we just need to find the y intercept.

and we will use the given coordinates to find the y intercept by putting in the x and y coordinates into the formula y=mx + b

-6= -2(1) + b

-6= -2 + b

+2 +2

b= -4

5 0

2 years ago

Please help !! Geometry homework. Will mark brainliest answer !

sergeinik [125]

For this case we have:

By trigonometric property we have:

$Cosine(\alpha)=\frac{AdjacentLeg}{Hypotenuse}$

Where:

$Adjacent Leg = 12\\Hypotenuse = 13\\\alpha= x$

Substituting:

$Cosine(x)=\frac{12}{13}$

Clearing x we have:

$x =Cosine^{-1}(\frac{12}{13})$

Thus, the equation is: $x =Cosine^{-1}(\frac{12}{13})$

Answer:

$x =Cosine^{-1}(\frac{12}{13})$

3 0

2 years ago