C is the answer of this problem
6n−20=−2n+4(1−3n)
Simplify both sides of the equation.
−6n−20=−2n+4(1−3n)
−6n+−20=−2n+(4)(1)+(4)(−3n)(Distribute)
−6n+−20=−2n+4+−12n
−6n−20=(−2n+−12n)+(4)(Combine Like Terms)
−6n−20=−14n+4
−6n−20=−14n+4
Add 14n to both sides.
−6n−20+14n=−14n+4+14n
8n−20=4
Add 20 to both sides.
8n−20+20=4+20
8n=24
Divide both sides by 8.
8n/8 = 24/8
n=3
Answer:
The chance of an average six-sided number cube landing one one number is 1/6, or approximately 16.67%. When rolling a number cube 100 times, the average number of times it lands on any specific number should be fairly close to 16.67.
A 6 being rolled 42 times and 33 times means that it is <em>very likely</em> not to be a standard number cube. Although we cannot know for certain, the chance of this happening is very low.
-2x < = 3x + 1 < = 10
split them
-2x < = 3x + 1 3x + 1 < = 10
-2x - 3x < = 1 3x < = 10 - 1
-5x < = 1 3x < = 9
x > = -1/5 x < = 3
solution is : -1/5 < = x < = 3 <==
hello since we are simplifying 15^-3*15^6 all we have to do is add the exponents when we add them we end up with an answer of 15^3