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2 years ago

Help please !!!!! i dont know how

Mathematics

1 answer:

dem82 [27]2 years ago

8 0

hello since we are simplifying 15^-3*15^6 all we have to do is add the exponents when we add them we end up with an answer of 15^3

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the sum of three numbers is 15. the second number is double the first. the third number is 5 less than the first. what are the t

tigry1 [53]

Hello from MrBillDoesMath!

Answer:

5, 10, 0

Discussion:

Let "f" be the first number. Then the questions tells us that

f + 2f + (f-5) = 15 =>

f + 2f + f - 5 = 15 => add 5 to both sides

4f = 5+ 15 = 20 => divide both sides by 4

f = 20/4 = 5

The numbers as

f: 5

2f: 10

(f-5): 0

Thank you,

MrB

5 0

2 years ago

PLEASE HELPO MEEEEEEE Choose ALL the real-world scenarios below that would represent the

Kamila [148]

Answer:

I just need points

Step-by-step explanation:

I just need points

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2 years ago

Find the slope-intercept form of the equation of the line that has the given properties (m is the slope). passes through (2, 2);

Mkey [24]

Y = -1x+b
replace x and y to find b
2 = -1*2+ b
b = 4

Final:
y = -1x + 4

7 0

2 years ago

The angle of the roof on Wendy's dollhouse is 56 degrees she built a scale model of the dollhouse with a scale ratio of 1 to 4 w

Sliva [168]

The angle of the roof on Wendy's dollhouse is 56 degrees she built a scale model of the dollhouse with a scale ratio of 1 to 4 what is the measurement of the angle of the roof of the model?

Answer: 14

4 0

2 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

2 years ago