The frequency of rotation of Mars is 0.0000113 Hertz.
<u>Given the following data:</u>
- Period = 1 day and 37 minutes.
To find the frequency of rotation in Hertz:
First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.
<u>Conversion:</u>
1 day = 24 hours
24 hours to minutes = × = minutes
1 minute = 60 seconds
1477 minute = X seconds
Cross-multiplying, we have:
×
X = 88620 seconds
Now, we can find the frequency of rotation of Mars by using the formula:
<em>Frequency </em><em>of rotation</em> = <em>0.0000113 Hertz</em>
Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.
Read more: brainly.com/question/14708169
Answer:
Superconducting materials can transport electrons with no resistance, and hence release no heat, sound, or other energy forms. Superconductivity occurs at a specific material's critical temperature (Tc). As temperature decreases, a superconducting material's resistance gradually decreases until it reaches critical temperature. At this point resistance drops off, often to zero, as shown in the graph at right.
Explanation:
A). Convection is heating the soup in the pot.
When you stick the spoon into the hot soup,
conduction heats the spoon all the way up to the end.
b). Water conducts heat a little bit.
But convection is much more responsible for the
uniform distribution of temperature in the kiddie pool.
c). The heat from the metal bench conducts directly
to the buttus epidermis when you sit on it.
d). You feel the heat on your face ... but not on the back of your
neck ... on account of radiation from the fire and the hot grill.
Galaxies are sprawling systems of dust, gas, dark matter, and anywhere from a million to a trillion stars that are held together by gravity. Nearly all large galaxies are thought to also contain supermassive black holes at their centers.
Answer:
Explanation:
As we know that electric field due to infinite line charge distribution at some distance from it is given as
now we need to find the electric field at mid point of two wires
So here we need to add the field due to two wires as they are oppositely charged
Now we will have
now plug in all data
now we have