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2 years ago

14

Carmen Reads 2 books eachmonthaspartofher Book Club. If Carmen has read 4books so far,how many months has he been with her bookc

lub?

2 answers:

Xelga [282]2 years ago

7 0

The answer would be 2 months because she has read 4 books and they read 2 a month so, 2 months.

pentagon [3]2 years ago

3 0

2 months

2m=4
divide 2
m=2

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Sweet Ems Candy Shop is selling candy for $0.89 a pound or you can get a 5-lb bag for $4.10. Yum Yum Candy Store across the stre

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2 years ago

Please help me it’s emergency please

Lostsunrise [7]

Answer:

$1.012 \times {10}^{ - 4}$

Step-by-step explanation:

move the decimal so there is one non-zero digit to the left of the decimal point. the number of decimal places you move will be the exponent on the 10. if the decimal is being moved to the right, the exponent will be negative. if the decimal is being moved to the left, the exponent will be positive.

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2 years ago

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A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo

djverab [1.8K]

Answer:

a) $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) $31690.7 g/L$

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is $\frac{dy}{dt}=R_{i}-R_{o}$ , where $R_{i}$ is the rate of salt entering and $R_{o}$ is the rate of salt going outside.

Then we have, $R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}$ , and

$R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}$

So we obtain. $\frac{dy}{dt}=4000-\frac{2y}{25}$ , then

$\frac{dy}{dt}+\frac{2y}{25}=4000$ , and using the integrating factor $e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}$ , therefore $(\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}$ , we get $\frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}$ , after integrating both sides $y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C$ , therefore $y(t)= 50000 +Ce^{\frac{-2t}{25}}$ , to find $C$ we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions $y(0)=10$ , so $10= 50000+Ce^{\frac{-0*2}{25}}$

$10=50000+C\\C=10-50000=-49990$

Finally we can write an expression for the amount of salt in the tank at any time t, it is $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) The tank will overflow due Rin>Rout, at a rate of $80 L/min-40L/min=40L/min$ , due we have 500 L to overflow $\frac{500L}{40L/min} =\frac{25}{2} min=t$ , so we can evualuate the expression of a) $y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7$ , is the salt concentration when the tank overflows

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2 years ago

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ZanzabumX [31]

Answer: The answer should be 3.

Step-by-step explanation: You plug in 2 instead of X and that’s it. Then you calculate your equation, and receive your answer.

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2 years ago

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sergij07 [2.7K]

Answer:

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Step-by-step explanation:

Google "central angles and inscribed angles geometry" for an explanation.

It's actually a poorly worded question.

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3 years ago

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