Answer:
- See below and the attachment
Step-by-step explanation:
<em>Refer to attached graph.</em>
<em>It i</em>ncludes the points and a best fit line produced by a graphing calculator.
- 17. The scatter plot is attached
- 18. There is a positive slope. Number of field goal attempts increase as minutes played increase.
- 19. The point is plotted: 2500 minutes gives about 880 field goal attempts.
The answer is 8 hoped that help always fell free to comment me if you have any more questions and always good luck
Answer: 6 pieces
=======================================================
Explanation:
3/4 = 6/8 after multiplying both parts by 2
We have a ribbon that is 6/8 of an inch long. We want to cut it into 1/8 inch pieces. We can see there will be exactly 6 pieces
Note how 6*(1/8) = 6/8
Or we can think of it as "we have a ribbon that is 6 units long and we want to cut it into pieces that are 1 unit each, so we'll have 6 pieces total". Replace "unit" with "1/8 inch" and you'll have the same idea.
This is the easiest way to solve this problem:
Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __
For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
<u>10</u> <u> 9 </u> <u> 8 </u> __
4th can't be repeated so only 7 options left
<u>10</u> <u> 9 </u> <u> 8 </u> <u> 7
</u><u>
</u>Multiply the four numbers together: 10*9*8*7 = 5040 combinations
For the next two do the same process as the one above.
If digits can be repeated? You have ten options for every wheel so it would look like this: <u>10</u> <u>10</u> <u>10</u> <u>10
</u>
10*10*10*10 = 10,000 combinations
If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.
<u>10</u> <u> 9</u><u> </u> <u> 9 </u> <u> 9 </u>
10*9*9*9 = 7290 combinations
Answer:
a¹⁰
Step-by-step explanation:
So here we have (a⁵)², meaning we need to multiply the exponents to get a¹⁰