Forces in direction x:
fx1 = 100 * cos (50) = 64.28
fx2 = 50 * cos (160) = - 46.99
The resultant is:
fx = fx1 + fx2 = 17.29
Forces in direction y:
fy1 = 100 * sine (50) = 76.60
fy2 = 50 * sine (160) = 17.10
The resultant is:
fy = fy1 + fy2 = 93.70
The magnitude of the resulting force is:
f = root (fx ^ 2 + fy ^ 2)
f = root ((17.29) ^ 2 + (93.70) ^ 2)
f = 95.28
The angle is:
theta = atan (fy / fx)
theta = atan (93.70 / 17.29)
theta = 79.55 degrees
Answer:
The direction and magnitude of the resultant force are:
f = 95.28 pounds at theta = 79.55 degrees
Answer:
45/r
Step-by-step explanation:
You're just doing 45 divided by r.
Answer:
I FIGURED IT OUT!
Step-by-step explanation:
a = 3
b = 3
c = 5
d = 2
give me brainliest
Answer:
B(-6, 0)
Step-by-step explanation:
You want to find B such that ...
(B -A) = (3/4)(C -A) . . . . the required distance relation
4(B -A) = 3(C -A) . . . . . . multiply by 4
4B = 3C +A . . . . . . . . . . add 4A, simplify
Now, we can solve for B and substitute the given coordinates:
B = (3C +A)/4 = (3(-6, -2) +(-6, 6))/4 = (-24, 0)/4 = (-6, 0)
The coordinates of point B are (-6, 0).
Hope it helped u if yes mark me BRAINLIEST!
Tysm!
:D
