This is the concept algebra.
Volume of of paint that is required to paint large shipping crate is a liters.
suppose the volume of this crate is x cubic units.
The volume of the next crate to be painted will be 2x cubic units.
Hence the amount of paint required to paint the crate will be:
(volume of bigger crate)/(volume of smaller crate)×(volume of liters required to paint the first crate)
=(2x)/(x)×a
=2a liters
To paint the new crate 2a liters of oil is needed.
Answer:B
Step-by-step explanation:
Answer:
Part A: 8b -12c -16
Part B: 4(2b - 3c -4)
Part C: 36
Step-by-step explanation:
Part A:
5b + 3c - 20 + 3b - 15c + 4
= 8b -12c -16
Part B:
Factorising 8b -12c -16
= 4(2b - 3c -4)
Part C:
= 4[2(2)-3(-3)-4)]
= 4[4+9-4]
= 4[9]
= 36
Set up a system of equations.
X+y=6
Y-x =40
Substitution method.
Y=6-x
(6-x)-x =40
6-2x=40
-2x=34
X= -17
Plug it back into the equation.
-17+y=6
Y=33
(-17,33) is one of the possible answers.
