The wire, the pole and the segment joining the leg of the pole to the wire in the ground form a right triangle whose hypotenuse is the wire, and the side opposite to the angle 36° is the pole.
By right triangle trigonometry, sin36°=(opposite side)/(hypotenuse.)
Substituting, we have 0.588=(opposite side)/220, thus the length of the opposite side, which represents the length of the pole, is
0.588*220 ft=129.3 ft
Mean is the "meanest" because it requires the most work. Add up the values in your data set and divide by the number of terms in the data.
Let x represent attendees at Harry's Hoedown, then
Mean =
41 =
123 = 48 + 33 + x
123 = 81 + x
42 = x
Answer: 42
Answer: m = 5/8
Step-by-step explanation:
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
Answer:
No
Step-by-step explanation:
The sequence is not an arithmetic sequence. For a sequence to be arithmetic, the difference between consecutive terms is a constant number which is termed as the common difference.
This means that the difference between the second term and the first term must be equal to the difference between the third term and the second term.
In the sequence above, the first term is 10. The difference between the first and second term is 15. When the first term is subtracted from the second, what we get is 5.
Now, let’s look at the third term and the second term. The difference here is 21 minus 15 which equals 6. Now we can see that the common difference is not constant and thus we conclude that the series is not arithmetic.