What is the volume of a sphere with a diameter of 7.9 ft

Mathematics

1 answer:

vovangra [49]2 years ago

5 0

Answer:

V ≈ 258 ft³

Step-by-step explanation:

I given the diameter d= 7.9 ft so the radius is r = d/2 = 7.9/2 ft

Volume of a sphere is

V = (4/3) π·r³ = (4/3) · π · (7.9/2)³ = 258.1546167 ft³

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Karo-lina-s [1.5K]

Answer: see below

Step-by-step explanation:

3x-12=7x+8 ⇔ given

-12=4x+8 ⇔ addition property of equality

-20=4x ⇔ subtraction property of equality

x=-5 ⇔ division property of equality

-----------------------

5(x-1)=4x+13 ⇔ given

5x-5=4x+13 ⇔ distributive property

x-5=13 ⇔ subtraction property of equality

x=18 ⇔ addition property of equality

3 0

2 years ago

Solve the equation <img src="https://tex.z-dn.net/?f=%2835%20x%5E%7B4%7D%20y%2B14%20x%5E%7B5%7D%20y-2%20y%5E%7B3%7D-4x%20y%5E%7B

jeka94

$\underbrace{35x^4y+14x^5y-2y^3-4xy^3}_M\,\mathrm dx+\underbrace{7x^5-6xy^2}_N\,\mathrm dy=0$

$M_y=35x^4+14x^5-6y^2-12xy^2$
$N_x=35x^4-6y^2$

$\dfrac{N_x-M_y}N=\dfrac{-14x^5+12xy^2}{7x^5-6xy^2}=-2$

This suggests an integrating factor depending on $x$ only is possible, and given by

$\mu(x)=\exp\left(-\displaystyle\int\frac{N_x-M_y}N\,\mathrm dx\right)=e^{2x}$

Distributing across the ODE, we end up with

$\underbrace{(35x^4y+14x^5y-2y^3-4xy^3)e^{2x}}_{M^*}\,\mathrm dx+\underbrace{(7x^5-6xy^2)e^{2x}}_{N^*}\,\mathrm dy=0$

The equation is now exact, with

${M^*}_y={N^*}_x=(35x^4+14x^5-6y^2-12xy^2)e^{2x}$

Now we find the solution:

$F_x=M^*$
$F=\displaystyle\int(35x^4+14x^5-2y^3-4xy^3)e^{2x}\,\mathrm dx$
$F=(7x^5y-2xy^3)e^{2x}+f(y)$

$F_y=N^*$
$(7x^5-6xy^2)e^{2x}+f'(y)=(7x^5-6xy^2)e^{2x}$
$f'(y)=0$
$\implies f(y)=C$

The general solution is then

$F(x,y)=(7x^5y-2xy^3)e^{2x}=C$