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2 years ago

What is temperature?

Physics

1 answer:

FromTheMoon [43]2 years ago

8 0

Answer:

B a measure of the amount of matter in an object

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Two ice boats (one of mass m, one of mass 2m) hold a race on a frictionless, horizontal, frozen lake. Bath ice boats start at re

Elenna [48]

Answer:

They both cross the finish line with the same kinetic energy

Explanation:

Same force, same displacement, so same KE at the location of the finish line. They don’t cross the line at the same time, but that was not the question!

∆KA= (mA/2)vF,A2

∆KA=∆KBso vF,B/vF,A= (MA/MB)1/2∆KB= (mB/2)vF,B2

Lighter boat goes faster so reaches finish line 1st

5 0

2 years ago

A car speeds up from 14 meters per second to 21 meters per second in 6 seconds. Whats the acceleration and the distance passed w

Solnce55 [7]

Answer:

a = 1.666... m/s²

Explanation:

a = v2 - v1 / t2 - t1

a = 21m/s - 14m/s / 6s - 0s

a = 7m/s / 6s

a = 1.666... m/s²

7 0

1 year ago

The electric potential at the dot in the figure is 3160 V. What is charge q?

PSYCHO15rus [73]

Hi there!

Recall the equation for electric potential of a point charge:

$V = \frac{kQ}{r}$

V = Electric potential (V)
k = Coulomb's Constant(Nm²/C²)

Q = Charge (C)
r = distance (m)

We can begin by solving for the given electric potentials. Remember, charge must be accounted for. Electric potential is also a SCALAR quantity.

Upper right charge's potential:

$V = \frac{(8.99*10^9)(-5 * 10^{-9})}{0.04} = -1123.75 V$

Lower left charge's potential:

$V = \frac{(8.99*10^9)(5*10^{-9})}{0.02} = 2247.5 V$

Add the two, and subtract from the total EP at the point:

$3160 + 1123.75 - 2247.5 = 2036.25$

The remaining charge must have a potential of 2036.25 V, so:

$2036.25 = \frac{(8.99*10^9)(Q)}{\sqrt{0.02^2 + 0.04^2}}\\\\2036.25 = \frac{(8.99*10^9)Q}{0.0447} \\\\Q = 0.000000010127 = \boxed{10.13nC}$

5 0

1 year ago

In the Millikan oil drop experiment the measured charge of any single droplet was always a whole number multiple of -1.60 x 10-1

BaLLatris [955]

Answer:

Number of electrons, n = 6

Explanation:

Total charge in a single droplet, $q=-9.6\times 10^{-19}\ C$

The measured charge of any single droplet, $e=-1.6\times 10^{-19}\ C$

Let n is the number of excess electrons are contained within the drop. According to the quantization of charge :

$q=ne$

$n=\dfrac{q}{e}$

$n=\dfrac{-9.6\times 10^{-19}}{-1.6\times 10^{-19}}$

n = 6

So, there are 6 electrons contained within the drop. Hence, this is the required solution.

7 0

2 years ago

Arrange these source charges in order from least to greatest magnitude.

Anestetic [448]

C ,A ,B ,D

I think I’m to sure

5 0

2 years ago

Read 2 more answers