Work = (force) x (distance)
1,008 J = (force) x (28 m)
Divide each side by 28m : (1,008 kg-m²/sec²) / (28 m) = force
Force = 36 kg-m/s² = 36 Newtons .
(about 8.1 pounds)
It doesn't matter what that force accomplishes.
It could be moving a brick, lifting a fish, or pushing a little red wagon.
In order to do 1,008 joules of work in 28 meters, it takes 36 N of force,
in the direction of the 28 meters.
Answer:
Magnetic field, B = 0.275 T
Explanation:
Given that,
Length of the wire, L = 35 cm = 0.35 m
Current carried in the wire, I = 2.6 A
The segment makes an angle of 53∘ with the direction of the magnetic field,
Magnetic force, F = 0.2 N
To find,
The magnitude of the magnetic field.
Solution,
The magnetic force acting on the wire is given by :
is the angle between the length of wire and the magnetic field.
B = 0.275 T
Therefore, the magnitude of the magnetic field is 0.275 T. Hence, this is the required solution.
Answer:
d = 142.5 m
Explanation:
This is a vector exercise. Let's calculate how much the boat travels in the 40s
d₀ = t
d₀ = 0.75 40
d₀ = 30 m
Let's write the kinematic equations
Boat
x = d₀ + t
x = 0 + t
At the meeting point the coordinate is the same for both
d₀ + t = t
t ( - ) = d₀
t = d₀ / ( - )
The two go in the same direction therefore the speeds have the same sign
t = 30 / (0.95-0.775)
t = 150 s
The distance traveled by man is
d = t
d = 0.95 150
d = 142.5 m
Answer:
Explanation:
f = Frequency = 75 Hz
B = Magnetic field =
d = Diameter of cell =
t = Time taken
= Angular frequency
The expression of emf is
Emf is maximum when and N = number of turns = 1
The maximum emf that can be generated around the perimeter of a cell in this field is