Answer:
24 years
Step-by-step explanation:
We are told that the model of number of deers is;
y = 0.75x² + 10.5x + 1300
Where;
y represents number of deers
x represents number of years
Now, we want to find how many years it will take to get to 2000 deers.
Thus;
2000 = 0.75x² + 10.5x + 1300
0.75x² + 10.5x + 1300 - 2000 = 0
0.75x² + 10.5x - 700 = 0
Using quadratic formula, we have;
x = [-b ± √(b² - 4ac)]/2a
x = [-10.5 ± √(10.5²- (4*0.75*-700)]/(2*0.75)
x = [-10.5 ± √(110.25 + 2100)]/(1.5)
x = [-10.5 ± √2210.25]/(1.5)
x ≈ -38 or 24
Number of years can't be negative, so we will take the positive value.
So, x = 24 years
Step-by-step explanation:
90 cents is ur answer i believe
Answer:
-0.04x +17.2
Step-by-step explanation:
We are given with a limit and we need to find it's value so let's start !!!!
But , before starting , let's recall an identity which is the <em>main key</em> to answer this question
Consider The limit ;
Now as directly putting the limit will lead to <em>indeterminate form 0/0.</em> So , <em>Rationalizing</em> the <em>numerator</em> i.e multiplying both numerator and denominator by the <em>conjugate of numerator </em>
Using the above algebraic identity ;
Now , here we <em>need</em> to <em>eliminate (√x-2)</em> from the denominator somehow , or the limit will again be <em>indeterminate </em>,so if you think <em>carefully</em> as <em>I thought</em> after <em>seeing the question</em> i.e what if we <em>add 4 and subtract 4</em> in <em>numerator</em> ? So let's try !
Now , using the same above identity ;
Now , take minus sign common in <em>numerator</em> from 2nd term , so that we can <em>take (√x-2) common</em> from both terms
Now , take<em> (√x-2) common</em> in numerator ;
Cancelling the <em>radical</em> that makes our <em>limit again and again</em> <em>indeterminate</em> ;
Now , <em>putting the limit ;</em>
The answer is x=
-3
Hope I helped!