I hope this helps. Since there are verticale angles that’s why I added another x.
The percentage of the radioactive isotope left is 25.0000%.
<h3>What is the half life?</h3>
The half life of a radioactive isotope is the time that will elapse before only half of the number of original isotopes will remain.
Now;
We are told that;
Half life (t1/2) = 55 days
Time taken (t) = 115 days
Ratio of isotope remaining = N/No
Thus;
N/No = (1/2)^t/t1/2
N/No = (1/2)^115/55
N/No = (1/2)^2
N/No =1/4
Hence, the percentage = 1/4 * 100/1 = 25.0000%
Learn more about half life of an isotope:brainly.com/question/16387602
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Answer:
B
Step-by-step explanation:
First calculate BD using sine ratio in Δ BCD and the exact value
sin60° = , thus
sin60° = = = = ( cross- multiply )
2BD = 12 ( divide both sides by 2 )
BD = 6
-----------------------------------------------------------
Calculate AD using the tangent ratio in Δ ABD and the exact value
tan30° = , thus
tan30° = = = = ( cross- multiply )
AD = 6 ( divide both sides by )
AD = 6 → B
Answer:
First Step: separate x^2 from -16
Second Step: add -16/25 to the other side.
Step-by-step explanation:
x^2 - 16/25 = 0
^^ this might be easier if you separate x^2 and -16
<em>First Step-</em>
so rewrite the problem as x^2/25 -16/25 = 0
then...
<em>Second Step-</em>
add -16/25 to the other side. This makes it: x^2/25 = 16/25
<em>Continuation-</em>
Now, you can multiply 25 on both sides to cancel it out.
so you have x^2 = -16
Message me if you want to solve for x.