Answer:
(a). The distance traveled by the car and trailer before they come to stop is 132.32 m
(b). The horizontal component of the force [N] exerted by trailer hitch onto the car is 2560 N.
Explanation:
Given that,
Mass of trailer = 1100 kg
Mass of car = 3200 kg
Speed of car and trailer = 60 km/h =16.67 m/s
Braking force on the car= 3700 N
Braking force on the trailer = 800 N
We need to calculate the acceleration
Using formula of acceleration
Where, F = total force
m = total mass
Put the value into the formula
(a). We need to calculate the distance traveled by the car and trailer before they come to stop
Using equation of motion
Put the value into the formula
(b). We need to calculate the horizontal component of the force exerted by trailer hitch onto the car
Firstly, we need to calculate the average braking force
Put the value into the formula
We need to calculate the net force on hitch
Hence, (a). The distance traveled by the car and trailer before they come to stop is 132.32 m
(b). The horizontal component of the force [N] exerted by trailer hitch onto the car is 2560 N.