Answer:
Explanation:
Let assume that pole vaulter begins running at a height of zero. The pole vaulter is modelled after the Principle of Energy Conservation:
The expression is simplified and final height is cleared within the equation:
![h_{B} = \frac{[(11\,\frac{m}{s} )^{2}-(1.3\,\frac{m}{s} )^{2}]}{2\cdot (9.807\,\frac{m}{s^{2}} )}](https://tex.z-dn.net/?f=h_%7BB%7D%20%3D%20%5Cfrac%7B%5B%2811%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D-%281.3%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%5D%7D%7B2%5Ccdot%20%289.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%29%7D)
Answer:
2.26l
Explanation:
From the general gas equation:
P1V1/T1 = P2V2/T2
Since pressure remained constant we can say:
V1/T1 = V2/T2
so to convert to kelvin add 273 to both temperature values then we can say:
1 m^3= 1000 L
2l=0.002m^3
Then;
0.002/308=V/348
V=(0.002/308)348
Final volume=0.002259m^3
=2.6l(1 decimal place)
Answer:
60 000 N
Explanation:
1 pa = 1 N/m^2
you have 300 000 of these = 300 000 N /m^2
but only an area of .2 m^2
300 000 N / m^2 * .2 m^2 = 60 000 N
(A)energy lost in the lever due to friction
(C)
visual estimation of height of the beanbag
(E)position of the fulcrum for the lever affecting transfer of energy
